Question

The sides of a triangle are in AP.the perimeter of the triangle is 30 cm and the difference between the longer and shorter side is 4 cm.find all sides of the triangle.

Answer 1

Answer:

Step-by-step explanation:

Let the shorter side be (a-2)cm

So the longer side = (a-2+4)cm = (a+2)cm

Since the sides are in AP third side = a cm.

So perimeter = a-2+a+2+a = 3a.

Given 3a = 30

So a=10

Sides of triangle are 8,10,12.