The sides of a triangle are in ratio 1 :2:2 . If the perimeter of the triangle is 500 meter square , find its area ?
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Answered by
8
Hey,
Let the sides be 1x, 2x and 2x,
So, perimeter = 500m^2
1x+2x+2x=500
5x=500
x=100m.
So, sides are 100m, 200m and 200m.
Now, area,
Semi-perimeter =100+200+200/2
=250m
So, area=√s(s-a) (s-b) (s-c)
=√250(250-100)(250-200)250-200
=√250*150*50*50
=9682.46m^2.
Hope this helps you buddy!!
TAKE CARE :-):-)
PLZ MARK AS BRAINLEST PLZ :-):-)
Let the sides be 1x, 2x and 2x,
So, perimeter = 500m^2
1x+2x+2x=500
5x=500
x=100m.
So, sides are 100m, 200m and 200m.
Now, area,
Semi-perimeter =100+200+200/2
=250m
So, area=√s(s-a) (s-b) (s-c)
=√250(250-100)(250-200)250-200
=√250*150*50*50
=9682.46m^2.
Hope this helps you buddy!!
TAKE CARE :-):-)
PLZ MARK AS BRAINLEST PLZ :-):-)
myselfyiri:
ur welcome, plz mark as brainlest
Answered by
5
hye
=====================
let the sides be 1x,2x and 2x
perimeter of rectangle = 1st side +2 nd side+3rd side
so lts from an equation
=>
=>
=>
=>
so 1x ,2x and 3x
=> 100x ,200x and 200x (multiply 100 for x)
=>[tex]Semi-perimeter =100+200+200/2 =250m [/tex]
=>So, area=√s(s-a) (s-b) (s-c)
=>=√250(250-100)(250-200)250-200
=√250*150*50*50
=9682.46m.²
===========================
hope it helps
=====================
let the sides be 1x,2x and 2x
perimeter of rectangle = 1st side +2 nd side+3rd side
so lts from an equation
=>
=>
=>
=>
so 1x ,2x and 3x
=> 100x ,200x and 200x (multiply 100 for x)
=>[tex]Semi-perimeter =100+200+200/2 =250m [/tex]
=>So, area=√s(s-a) (s-b) (s-c)
=>=√250(250-100)(250-200)250-200
=√250*150*50*50
=9682.46m.²
===========================
hope it helps
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