the sides of a triangle are in the proportion 3 is to 4 is to 5 and its perimeter is 48 metres find the area of triangle is it a right angle triangle
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let the first side be 3x
second side be 4x
third side be 5x
perimeter = a+b+c
48m = 3x+4x+5x
48m = 12x
48/12 = x
x= 4
first side = 3x = 12
second side = 4x = 16
third side = 5x = 20
now ,
by Pythagoras theorem,
20^2 = 12^2 + 16^2
400 = 144 + 256
400 = 400
hence it is a right triangle,
so area = 1/2 × base × height
= 1/2 × 12 × 16
= 96 m^2
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