In an election, there were two candidates A and B. The total number of voters in this constituency was the total votes were polied. If 68% of the polied votes were cast in favour of A,and 20340 vote more than B how many votes were received by A?
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Answer:
A received = 38420 Votes
Step-by-step explanation:
In an election, there were two candidates A and B. The total number of voters in this constituency was the total votes were polied. If 68% of the polied votes were cast in favour of A,and 20340 vote more than B how many votes were received by A?
Let say Total Votes were = 100V
as all votes Casted
so Polled Votes = 100V
A Received = (68/100) * 100V = 68V
B received = 100V - 68V = 32V
A received 68V - 32V = 36V more Votes than B
36V = 20340
1 = 20340/36V
68V = (20340/36V) * 68V = 38420
A received = 38420 Votes
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