Math, asked by vinyvibhav1132, 1 year ago

The sides of a triangle are of lenghts 15cm,36cm and 39cm.find the lenght of perpendicular from the opposite vertex to the side of lenght 39cm

Answers

Answered by smriti3008
12

Answer: 13.84

Step-by-step explanation:

We know that s=(a+b+c)/2

here, a=15,b=36, c=39.

Therefore: s= (15+36+39)/2

s=45

And area = \sqrt{s(s-a)(s-b)(s-c)}

Therefore: area= \sqrt{45(45-15)(45-36)(45-39)}

Area= 270.

Now, Let the height of the perpendicular be 'H'

And, as it is from the opposite vertex of side of the length 39; Base is 39.

According to the formula: area=(height * base)/2

Filling the information we have,

270 = (H * 39)/2

Therefore: H = 13.84

Hope this helps

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