Question

the sides of a triangle are x^2-3xy+8 4x^2+5xy-3 8.6-3x^2+4xy find its preimeter​

Answer 1

Answer:

plz follow........ ........

Answer 2

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Sides of a triangle = x² - 3xy + 8 , 4x² + 5xy - 3 , 6 - 3x² + 4xy

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Perimeter = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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$\sf{\red{\boxed{\bold{Perimeter = a + b + c}}}}$

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$\sf:\implies \: {\bold{ perimeter = x^2 - 3xy + 8 + 4x^2 + 5xy - 3 +6 - 3x^2 + 4xy }}$

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$\sf:\implies \: {\bold{ perimeter = x^2 + 4x^2 - 3x^2 -3xy + 5xy + 4xy + 8 - 3 + 6 }}$

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$\sf:\implies \: {\bold{ perimeter = 2x^2 - 3xy + 5xy + 4xy + 8 - 3 + 6 }}$

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$\sf:\implies \: {\bold{ perimeter = 2x^2 + 6xy + 8 - 3 + 6 }}$

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$\sf:\implies \: {\bold{ perimeter = 2x^2 + 6xy + 11}}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Required perimeter = 2x² + 6xy + 11