Question

The sides of a triangle are x, x+1 , 2x-1
And it's area is x√10 . Find the value of x

Answer 1

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Refer to the attachment

Answer 2

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QUESTION:-

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•The sides of a triangle are x, x+1 , 2x-1

And it's area is x√10 . Find the value of x.

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CONCEPT:-

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•(HERON FORMULA:)

the area of a triangle when the length of all three sides are known. Unlike other triangle area formulae, there is no need to calculate angles or other distances in the triangle first.

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SOLUTION:-

•semi perimeter = s1+s2+s3/2

.°. s = x+x+1+2x-1

.°. s=4x/2

.°. s=2x

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• area of Δ =√s(s-a) (s-b) (s-c)

:$\implies$ x√10 =√2x (2x -x) (2x -x+1)(2x -2x -1)

:$\implies$ x√10 =√2x. x (x-1).1

:$\implies$ x√10=√2x²(x-1)

:$\implies$ x√10=x√2(x-1)

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•SQUARING BOTH SIDE ,

then we get,

:$\implies$ 10=2(x-1)

:$\implies$10=2x-2

:$\implies$ 2x =10+2

:$\implies$ 2x =12

:$\implies$ $\red{x=6}$

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#learn more.

•https://brainly.in/question/15135595.

•https://brainly.in/question/15047349.

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