Question

The sides of a triangle are x, x+3, x+5. if the perimeter of the triangle is 29 cm, find its sides

Answer 1

Answer:

Given :-

• The sides of a triangle are x, x + 3, x + 5.
• The perimeter of the triangle is 29 cm.

To Find :-

• What is the sides of the triangle.

Solution :-

Let,

$\mapsto \bf First\: Side =\: x\: cm$

$\mapsto \bf Second\: Side =\: x + 3\: cm$

$\mapsto \bf Third\: Side =\: x + 5\: cm$

As we know that :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Perimeter_{(Triangle)} =\: Sum\: of\: all\: sides}}}\: \: \: \bigstar$

Given :

• Perimeter of the triangle = 29 cm.

According to the question by using the formula we get :

$\implies \sf x + x + 3 + x + 5 =\: 29$

$\implies \sf x + x + x + 3 + 5 =\: 29$

$\implies \sf 3x + 8 =\: 29$

$\implies \sf 3x =\: 29 - 8$

$\implies \sf 3x =\: 21$

$\implies \sf x =\: \dfrac{\cancel{21}}{\cancel{3}}$

$\implies \sf\bold{\purple{x =\: 7}}$

Hence, the required sides of a triangle are :

$\footnotesize \dashrightarrow \sf\bold{\red{First\: Side_{(Triangle)} =\: x\: cm =\: 7\: cm}}$

$\footnotesize \dashrightarrow \sf\bold{\red{Second\: Side_{(Triangle)} =\: x + 3 =\: 7 + 3 =\: 10\: cm}}$

$\footnotesize \dashrightarrow \sf\bold{\red{Third\: Side_{(Triangle)} =\: x + 5 =\: 7 + 5 =\: 12\: cm}}$

$\therefore$ The sides of a triangle is 7 cm, 10 cm and 12 cm respectively.

Answer 2

To find : sides of triangle .

Given : sides of triangle are $x ,x+ 3, x+5$

            perimeter of triangle is $29\ cm$ .

Solution :  

• As per given data we know that sides of triangle are  $x ,x+ 3, x+5$ and  perimeter of triangle is $29\ cm$ .
• We know that , perimeter of triangle is given by ;
• $a + b + c =29$
• $x + x + 3 +x + 5 =29$

       $3x+ 8 = 29 \\3x = 29-8 \\x = \frac{21}{3} \\x = 7$

• We find the sides of triangle by substituting the value of $x$ .  

       $x =7\ cm \\x + 3 =7 + 3 =10\ cm \\x + 5 =7 + 5 = 12\ cm$

Hence , sides of triangle are $7\ cm , 10\ cm , 12\ cm$ .