. The sides of a triangular field are 120m, 160m and 200m. Find the cost of ploughing it at 25 paise per sq.m.
Answers
Answer:
₹2400
Step-by-step explanation:
Taking a close look at the values of sides of triangle,
we come to know that it is a right angle triangle
since 120²+160²=200²
thus sides with measures 120m and 160m make right angle
thus they are base and height
cost of ploughing= rate*area
=25*(1/2*b*h)paise
=25*9600paise
=240000paise
=₹2400
Answer:
semiperimeter= 120+160+200/2
=480/2
=240
now to find the area, we will use herons formula;
area= √240(240-120) (240-160) (240-200)
=√ 240×120× 80× 4× 10^4 { in this one i took out
the 0s writing 10^4 as
there 4 zeros in total}
= √2×2×2×3×2×2×3×2×2×2×2×2×10000
= 2×2×3×2×2×2×100
= 9600 m^2
cost of ploughing per m ^2= 25 paise
cost of ploughing 9600m^2 = 9600× 25
= 240000 paise
=₹ 2400( as 1 rupee = 100
paise)
i hope it helps u....
regards Rohani Mohanty