Question

the
sides of a triangular field are
41m, 40 m, and 9m. find the no. of
rose bed that can be
prepared in the field if each
bed takes 900 cm^2 space.
Also find the cost of preparing
the beds if one cost 5000 rupees.
​

Answer 1

Step-by-step explanation:

area of triangle=√s(s-a)(s-b)(s-c)

s(semiperimeter)=a+b+c/2

=90/2=45

area of triangle=√45×4×5×36

=√25×9×144

=5×3×12=180m^2=180×10^4

no. of beds possible=2000

cost of preparing=2000×5000=10^7