Question

Xtra Questions
(If the sum of squares of zeroes of polynomial x²-8x+k is 40.find the valve Of K.)​

Answer 1

Answer:

k=12

Step-by-step explanation:

Given:-

sum of squares of zeroes of polynomial is 40. Let the zeroes be 'a' and 'b'.

a²+b²=40

(a+b)²-2ab=40-------(I)

we know that...

a+b= -b/a= 8

a*b= c/a= k----put in (I)

(8)²-2k=40

64-40=2k

24=2k

[ k=12 ]--------Ans

Answer 2

Answer:

For k=12,the sum of squares of zeros of the given polynomial is 40.

Step-by-step explanation:

Let the polynomial be f(x)

f(x)=x²-8x+k

Let @ and ß be the zeros

Given that,

@²+ß²=40

Here,

@+ß=8 and, @ß=k

Now,

@²+ß²=40

→(@+ß)²-2@ß=40

→(8)²-2(k)=40

→64-2k=40

→2k=24

→k=12