Question

The sides of a triangular field are 9 m, 10 m and 17 m. Find the number of rose beds that can be prepared in the field, if each rose bed, on an average needs 600 cm2 space

Answer 1

Answer:

Area of triangular field

s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√

s=a+b+c2=41+40+92=45m

Area=45×(45−41)×(45−40)×(45−9)−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√

=45×4×5×36−−−−−−−−−−−−−√=180m2=1800000cm2

Number of rose bed =1800000900=2000.

Answer 2

Step-by-step explanation:

The sides of the triangular field are :

a= 9m= 900 cm

b= 10 m = 1000cm

c = 17m = 1700 cm

so, 2s= a+ b + c

= 900 +1000+1700

= 3600cm

so, s=3600cm ÷2

= 1800cm

Now Area of the triangular field is

$= \sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{1800(1800 - 900)(1800 - 1000)(1800 - 1700)} cm {}^{2}$

$= \sqrt{1800 \times 900 \times 800 \times 100} cm {}^{2}$

$= \sqrt{3 {}^{ 4} \times2 {}^{4} \times 100 {}^{4} }$

$= 3 {}^{2} \times 2 {}^{2} \times 100 {}^{2}$

$= 360000cm {}^{2}$

So the no of rose beds can be prepared is

= 360000÷ 600

=600