the sides of an equilateral triangle are increasing at the rate of 2cm/s. find the rate at which the area increases when the side of the triangle is 10cm
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let x is the side of equilateral triangle
area of equilateral triangle(A)=(root3/4)x^2
A=(root3/4 )x^2
now differentiate w.r.t t
dA/dr=(root3/2)x .dx/dt
dA/dt=(root3/2)(10)(2)
=10root3 cm^2/sec
area of equilateral triangle(A)=(root3/4)x^2
A=(root3/4 )x^2
now differentiate w.r.t t
dA/dr=(root3/2)x .dx/dt
dA/dt=(root3/2)(10)(2)
=10root3 cm^2/sec
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