A triangle PQR circumscribes a circle of radius r such that angle Q=90 degree (angle) Given that, PQ = 3 cm and QR = 4 cm. Find the radius of the circle.
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Use Pythagoras theorem in different triangles...
PO^2= (3-r)^2+ r^2 = PC^2 + r^2
PC = PA = 3 -r
As PR=5 cm, CR = r+2 cm
RO^2 = (r+2)^2 + r^2 = BR^2 + r^2
So BR = r+2 = 4-r
=> r = 1 cm
PO^2= (3-r)^2+ r^2 = PC^2 + r^2
PC = PA = 3 -r
As PR=5 cm, CR = r+2 cm
RO^2 = (r+2)^2 + r^2 = BR^2 + r^2
So BR = r+2 = 4-r
=> r = 1 cm
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