Question

the sides of rectangle are 2m and 1.5m the length of its diagonal is​

Answer 1

Hello Friend

Here is your answer below,

Given values are, length of rectangle is. 2m

and Breadth of the rectangle is. 1.5m

so diagonal of the rectangle is 2.5m

Here is your explanation,

if we meet the corner of rectangle we will find a right angled triangle

so

hypotenuse^2 = length^2+ Breadth^2 (here

hypotenuse means diagonaln)

hypotenuse^ 2= 2^2+1.5^2

hypotenuse = √(4+2.25)

hypotenuse = √6.25

hypotenuse = 2.5 m

I hope that helps you

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Answer 2

Information given in the question:

• Length=2m
• Breadth=1.5m

What to find:

$\to$The length of it's diagonal

Solution:

Let,

$\to$Length be $l$

$\to$Breadth be $b$

According to pythagoras theorem:

$\to$The diagonal of the rectangle=$\sqrt{l^2+b^2}$

According to the question:

The diagonal of the rectangle with sides 2m and 1.5m=

$\to\sqrt{2^2+1.5^2}$ m

$\to =\sqrt{4+2.25}$ m

$\to =\sqrt{6.25}$ m

$\to =\sqrt{2.5 * 2.5}$ m

$\to =2.5$ m

Additional information:

$\to$The perimeter of the rectangle=$2(Length+Breadth)$

$\to$The area of the rectangle=$(Length*Breadth)$

Answer:

The diagonal of the rectangle with sides 2m and 1.5m=2.5m