Math, asked by karan19683, 1 year ago

the sides of rectangular field are in the ratio of 5 ratio 9 if the length of fencing 5600 metre find the sides of field and area of field ​

Answers

Answered by GodOfThunder123
102

perimeter=2(5x+9x)

=28x=5600m

=x=5600/28=200m

first side=5*200=1000m

second side=9*200=1800m

area=lb=1000*1800=1800000m^2

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Answered by Sauron
128

\textbf{\underline{\underline{Answer :-}}}

The area of the Rectangle is 18,00,000 sq.m

\textbf{\underline{\underline{Explanation :-}}}

\textsf{\underline{\underline{Given :}}}

Ratio of the sides = 5 : 9

Length of Fencing = 5600 m

\textsf{\underline{\underline{To find :}}}

The measure of sides and it's area.

\textsf{\underline{\underline{Solution : }}}

Consider the Breadth as 5x

Consider the Length as 9x

The length of Fencing is actually the measure of the Perimeter.

Perimeter of Rectangle =

\boxed{\sf{2(Length+Breadth)}}

\sf{\implies} \:2(5x + 9x) = 5600 \\\sf{\implies} \:10x + 18x = 5600 \\ \sf{\implies} \:28x = 5600 \\ \sf{\implies} \:x =  \frac{5600}{28} \\\sf{\implies} \:x = 200

Value of 5x

\implies 5 × 200

\implies 1000

Value of 9x

\implies 9 × 200

\implies 1800

Breadth = 1000 m

Length = 1800 m

\rule{300}{1}

Area of the Rectangle :

\boxed{\sf{Length \times Breadth}}

\sf{\implies} \: 1000 \times 1800 \\ \sf{\implies} \: 1800000

\therefore The area of the Rectangle is 18,00,000 sq.m


Swetha02: Awesome!
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