Question

the sides of the triangle are 35,54,61 respectively find the longest altitude​

Answer 1

let us consider

A = 35 ( side),

B = 54 (base),

C = 61 (side).

a+b+c / 2 => 35 +54 +61 / 2 => 75

Area, A = √s(s – a)(s — b)(s — c) => √/75 (75-35) (75 – 54) (75 – 61) =>

420√5cm²

Now, Area of the triangle is also given as A = 1/2 x a x h

Where, h is the longest altitude. Therefore, 1/2 x a x h = 420√5

Hence, h = 24√//5 cm

hopes it's helpful