Question

The sides of the triangle are 94041 m. Find the length of the perpendicular placed on the 41 m long arm.

Answer 1

Answer:

In triangle ABC,

AB=9m, BC=40m & CA=41m

CA^2=41^2=1681

AB^2+BC^2=9^2+40^2

=>AB^2+BC^2=81+1600

=>AB^2+BC^2=1681

=>AB^2+BC^2=CA^2

=>CA^2=AB^2+BC^2

=> <B=90°(by converse of Pythagoras theorem)

Area of triangle ABC=1/2×base×perpendicular

=1/2×9×40

=180 m^2

Again, Area of triangle ABC=180 m^2

=>1/2×base×height=180 m^2

=>1/2×AC×height=180

=>1/2×41×height=180

=>height=(180×2)/41

=>height=8.78 m_________(ans)