Question

the sides of the triangle are x cm, x+1 cm and 2x-1 cm. its area is x10
square cm find the value of x

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Answer 1

Answer:

x=6

Step-by-step explanation:

Here

s=(x+x+1+2x-1)/2

=4x/2

=2x

Now Area=√[s(s-x){s-(x+1)}{s-(2x-1)}]

=√[2x(2x-x){2x-(x+1)}{2x-(2x-1)}]

=√[2x^2(2x-x-1)(2x-2x+1)]

=√[2x^2(x-1)×1]

=√(2x^3–2x^2)

According to question

√(2x^3–2x^2)=x√10

Or, {√(2x^3–2x^2)}^2={x√10}^2

Or, 2x^3–2x^2=10x^2

Or, 2x^3–10x^2–2x^2=0

Or,2x^3–12x^2=0

Or, 2x^2(x-6)=0

Either 2x^2=0

Or, x=0

/OR x-6=0

Or,x=6

But x can not be 0

therefore x=6