the sides of triangle are 3cm,3cm and 5cm.find its area
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Answered by
19
a = 3 cm
b = 3 cm
c = 5cm
s = (a+b+c)/2
= (3+3+5)/2
= 11/2
= 5.5 cm
Area of a triangle = √(s(s-a)(s-b)(s-c))
= √(5.5(5.5-3)(5.5-3)(5.5-5))
= √(5.5×2.5×2.5×0.5)
= √(0.5×11×0.5×5×0.5×5×0.5)
= 5×0.5×0.5√(11)
= 1.25√(11) cm
Hope it helps you all ☺
b = 3 cm
c = 5cm
s = (a+b+c)/2
= (3+3+5)/2
= 11/2
= 5.5 cm
Area of a triangle = √(s(s-a)(s-b)(s-c))
= √(5.5(5.5-3)(5.5-3)(5.5-5))
= √(5.5×2.5×2.5×0.5)
= √(0.5×11×0.5×5×0.5×5×0.5)
= 5×0.5×0.5√(11)
= 1.25√(11) cm
Hope it helps you all ☺
Answered by
17
Hi friend.solution to the question u asked is in the pic..okay plz regard as brainliest....hope it helps u..thank u good day
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