Question

the sides of triangle are 70 cm 100 cm and 122 CM the length of its longest altitude is​

Answer 1

Step-by-step explanation:

semiperimeterisequalto

2

(a+b+c)

=

2

(70+108+122)

=

2

300

=150

theheronformulaisequalto−

=

s(s−a)(s−b)(s−c)

=

150(150−70)(150−108)(150−122)

=

150×80×42×28

14,112,000

=3,756.60

nowwegottheareaoftriangle

since,theareaoftriangleisequalto

=

2

1

×b×h

hence,

3756.6=

2

1

×122×h

3756.6=61×h

h=

61

3756.6

=61.6