The sides of triangle are100m ,120m,&140 .find its area
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Answered by
9
Hey friend,
Here is the answer you were looking for:
Given,
The sides of triangle are 100m, 120m and 140m
Semi - perimeter: 100 + 120 + 140 / 2
s = 360 / 2
s = 180
So,
The area of triangle = √ s (s - a) (s - b) (s-c)
Area = √ 180 (180 - 100) (180 - 120) (180 - 140)
Area = √ 180 × 80 × 60 × 40
Area = √ 34,560,000
Area = 5878.77 m^2
HOPE MY ANSWER WOULD BE HELPFUL TO YOU!!!
AND IF YOU FOUND MY ANSWER HELPFUL, THEN PLEASE MARK AS BRAINLIEST.
THANKS...
☺☺
Here is the answer you were looking for:
Given,
The sides of triangle are 100m, 120m and 140m
Semi - perimeter: 100 + 120 + 140 / 2
s = 360 / 2
s = 180
So,
The area of triangle = √ s (s - a) (s - b) (s-c)
Area = √ 180 (180 - 100) (180 - 120) (180 - 140)
Area = √ 180 × 80 × 60 × 40
Area = √ 34,560,000
Area = 5878.77 m^2
HOPE MY ANSWER WOULD BE HELPFUL TO YOU!!!
AND IF YOU FOUND MY ANSWER HELPFUL, THEN PLEASE MARK AS BRAINLIEST.
THANKS...
☺☺
Answered by
2
by herons formula you can find the area first we can find semi perimeter(s)=a+b+c/2=100+120+140/2=360/2=180, the herons formula is finding for area of triangle is = underroot s(s-A)(s-B)(s-C)= underroot 180(180-100)(180-120)(180-140)= underroot 180(80)(60)(40)=underroot 34560000= 5878.77m square hope it helps you please mark it as a brainiest answer early
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