the sides of triangle x,x + 1, and 2x + 1 its area is xroot10 find x
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s, the semi-perimeter = 2.x
A = √[s.(s-a)(s-b)(s-c)] where a, b and c are the 3 sides. So:
A = x/√(10) = √[2x(x)(x-1)(1)] = √[2x³-2x²] which, simplified gives:
x²/10 = 2x³-2x² or 2x = 2.1 giving x= 1.05
A = √[s.(s-a)(s-b)(s-c)] where a, b and c are the 3 sides. So:
A = x/√(10) = √[2x(x)(x-1)(1)] = √[2x³-2x²] which, simplified gives:
x²/10 = 2x³-2x² or 2x = 2.1 giving x= 1.05
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