the sides of two cubes are in the ratio 1:3. what is the ratio of the areas of these cubes ?what is the ratio of their volumes?
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Answered by
14
Let the sides be a and 3a
Ratio of areas = 6 × (a)^2 / 6 × (3a)^2
= a^2 / 9a^2
= 1 : 9
Ratio of Volumes = a^3 / (3a)^3
= a^3 / 27a^3
= 1 : 27
Ratio of areas = 6 × (a)^2 / 6 × (3a)^2
= a^2 / 9a^2
= 1 : 9
Ratio of Volumes = a^3 / (3a)^3
= a^3 / 27a^3
= 1 : 27
Answered by
2
The ratio of their areas will be 1:9
and the ratio of their volumes will be 1:27
HOPE THAT IT IS RIGHT.
IF IT'S WRONG PLEASE TELL ME THE RIGHT ONE.
and the ratio of their volumes will be 1:27
HOPE THAT IT IS RIGHT.
IF IT'S WRONG PLEASE TELL ME THE RIGHT ONE.
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