the sides of two squaresare in th ratio of 5 : 7. find the ratio of their areas
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Answer:
side of square 1= 5x
" """"""""""""""" 2= 7x
area of square 1= (5x) ²
25x²
area of square 2= (7x) ²
49x²
ratio of there areas = area of sq. 1÷ area of sq. 2
25x²÷49x²
x² and x² cancels
ratio is 25:49
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Answer:
I Hope that I have Helped You
Step-by-step explanation:
- LET SIDE OF FIRST SQUARE is equal to 5x
- AND ,SIDE OF SECOND SQUARE is equal to7x
- THEREFORE,
- AREA OF FIRST SQUARE is equal to 25xsquare
- AND,AREA OF SECOND SQUARE is equal to 49xsquare
- RATIO OF AREAS is equal to 25xsquare/49xsquare is equal to 25/49
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