The simple interest on a certain principal for 3 years at 10%p.A is 300. Find the compound interest accrued in 3 years.
Answers
Answered by
8
Answer:
331
Step-by-step explanation:
SI=p x r x t/100
=>300=p x 10 x 3/100
=>300 x 100/30=p
=>p=1000
Therefore,CI=p[(1+r/100)^n-1]
=1000[(1+10/100)^3-1]
=1000[(11/10)^3-1]
=1000[1331-1000/1000]
=1000 x 331/1000
=331
Hope it helps you please mark my answer as brainlist.....
Similar questions