There are 128 pages in a logical address space, with a page size of 1024 bytes and a physical memory of 32 frames. How many bits are required to address the physical memory?
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Since the logical address space consists of 64 = 2 6 pages, the logical addresses must be 10+6 = 16 bits. Similarly, since there are 32 = 2 5 physical frames, physical addresses are 5 + 10 = 15 bits long.
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