The simple interest on a certain sum for 3 and half years at 7% p.a. is Rs.225 more than the simple interest on the same sum for 4 years at 5% p.a. Find the sum.
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Answered by
204
Let the sum be x
case (i)
Principle = x, Rate = 7%, time = 3.5 yrs
Interest =![\frac{PTR}{100} \frac{PTR}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7BPTR%7D%7B100%7D+)
=![\frac{x (7)(3.5)}{100} \frac{x (7)(3.5)}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx+%287%29%283.5%29%7D%7B100%7D+)
=![\frac{24.5x}{100} \frac{24.5x}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7B24.5x%7D%7B100%7D+)
case (ii)
Principle = x, Rate = 5%, time = 4 yrs
Interest =![\frac{PTR}{100} \frac{PTR}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7BPTR%7D%7B100%7D+)
=![\frac{x (5)(4)}{100} \frac{x (5)(4)}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7Bx+%285%29%284%29%7D%7B100%7D+)
=![\frac{20x}{100} \frac{20x}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7B20x%7D%7B100%7D+)
given that, the simple interest for case (i) is Rs 225 more than the simple interest for case (ii)
![\frac{24.5x}{100} - \frac{20x}{100} = 225 \frac{24.5x}{100} - \frac{20x}{100} = 225](https://tex.z-dn.net/?f=%5Cfrac%7B24.5x%7D%7B100%7D+-+%5Cfrac%7B20x%7D%7B100%7D+%3D+225)
= 225
x =![\frac{22500}{4.5} \frac{22500}{4.5}](https://tex.z-dn.net/?f=+%5Cfrac%7B22500%7D%7B4.5%7D++)
x = 5000
The sum = Rs 5000
case (i)
Principle = x, Rate = 7%, time = 3.5 yrs
Interest =
=
=
case (ii)
Principle = x, Rate = 5%, time = 4 yrs
Interest =
=
=
given that, the simple interest for case (i) is Rs 225 more than the simple interest for case (ii)
x =
x = 5000
The sum = Rs 5000
Answered by
13
Step-by-step explanation:
Let the principle be Rs. 100 in both the cases
SI for 3½ or 7/2 years at 7%=P*R*T/100 =100*7*7/2/100
=49/2
=Rs.24.5
SI for 4 years at 5%=100*5*4/100
=Rs.20
The difference is=Rs.24.5-Rs.20
=Rs.4.5
If the difference is Rs.4.5,the principal=Rs.100
If the difference is Rs.225,the principal
=100/4.5*225
=100*10*225/45
=Rs.5000
so,Rs.5000 was the sum in both the cases
Hope it helps
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