the simple interest on a certain sum of money and at 10% per annum is rupees 6000 in 2 years
Find a] the sum
b] the amount due to the end of 3 years and at the same rate of interest compounded annually
c] the compound interest earned
in 3 years
Answers
Answered by
29
si = 6,000
(p*10*2)/100 = 6,000
p = 6,000*5
p = 30,000
A = P [ 1+10/100]^3
A = 30,000 [1331/1000]
A = 36,630
ci = A-P
CI = 36,630 - 30,000
CI = 6,630
(p*10*2)/100 = 6,000
p = 6,000*5
p = 30,000
A = P [ 1+10/100]^3
A = 30,000 [1331/1000]
A = 36,630
ci = A-P
CI = 36,630 - 30,000
CI = 6,630
Rutvi2:
can you solve more
Answered by
5
Answer:
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Step-by-step explanation:
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