Question

the simple interest on a certain sum of money for 2 years at 11 by 2% is rupees 6600 what will be the compound interest on what some at the same rate for the same time period

Answer 1

Here,S.I=rs6600,R%=11/2%,T=2 years.
As we know that
S.I=P×R×T/100
rs6600=P×11×2/100×2
p=6600×100/11=rs60000


Now ,C.I
But first we will calculate its amount
Amount =p(1+R/100)^n
=60000(1+11/2×100)^2
=60000(1+11/200)^2
=60000(211/200)^2
=60000×211/200×211/200
=133563/2
=rs66781.50


Now,C.I=A-P
=rs(66781.50-60000)
=rs6781.50.

Hence,compound interest =rs6781.50.


HOPE! IT HELPS.

Answer 2

here is your answer

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