the simple interest on a sum of money for 2 years at 10% per annum is rupees 1700 find first the sum of money second the compound interest on this sum for first year payable half yearly at the same rate
Answers
Answered by
56
SI = 1700 ( given)
SI = P × R × To / 100
1700 = P × 10 × 2/100
P = 8500
CI = P[( 1 + r/2×100)^n×2 - 1]
CI = 8500[( 1 + 10/2×100)^2 - ]
CI = 8500[( 21/20)^2 - 1]
CI = 8500[ 441/400 -1 ]
CI = 8500[ 41/400 ]
CI = 871.25.
Hope it helps..........
SI = P × R × To / 100
1700 = P × 10 × 2/100
P = 8500
CI = P[( 1 + r/2×100)^n×2 - 1]
CI = 8500[( 1 + 10/2×100)^2 - ]
CI = 8500[( 21/20)^2 - 1]
CI = 8500[ 441/400 -1 ]
CI = 8500[ 41/400 ]
CI = 871.25.
Hope it helps..........
Answered by
14
Answer:
SI = 1700 ( given)
SI = P × R × To / 100
1700 = P × 10 × 2/100
P = 8500
CI = P[( 1 + r/2×100)^n×2 - 1]
CI = 8500[( 1 + 10/2×100)^2 - ]
CI = 8500[( 21/20)^2 - 1]
CI = 8500[ 441/400 -1 ]
CI = 8500[ 41/400 ]
CI = 871.25.
Hope it helps..........
Step-by-step explanation:
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