Question

The simple interest on Rs. 10000 for 73 days at 4%
Per annum is.​

Answer 1

Answer:

P=₹1000

R=10%

T=73days

SI=?

SI=P×R×T/100

SI=₹1000×73×10/100

SI=10×73×10

SI=₹7300

Their fore the SI on Rs 1000for 73 days at 10%pa is ₹7300.

Answer 2

Answer:

${\large{\pmb{\sf{\underline{\underline{Given...}}}}}}$

• $\dashrightarrow$ Principle = Rs.10000
• $\dashrightarrow$ Time = 73 days
• $\dashrightarrow$ Rate of Interest = 4%

${\large{\pmb{\sf{\underline{\underline{To \: Find...}}}}}}$

• $\dashrightarrow$ Simply Interest

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{Using \: Formula...}}}}}}$

$\quad\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

• $\leadsto$ S.I = Simple Interest
• $\leadsto$ SP = Principle
• $\leadsto$ SR = Rate of Interest
• $\leadsto$ ST = Time

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{Basic \: Terms ...}}}}}}$

• ➨ Simple Interest = Simple interest is the method of calculating interest charged on the amount invested in a fixed deposit.
• ➨ Principle = The principal is the amount due on any debt before interest, or the amount invested before returns
• ➨ Rate = An interest rate is the percentage of principal charged by the lender for the use of its money
• ➨ Time = Time is duration (in months or years) in Simple Interest

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{Solution...}}}}}}$

$\bigstar{\underline{\underline{\frak{\blue{Here \: :}}}}}$

• Principle = Rs.10000
• Rate of Interest = 4%
• Time = 73 days

Covereting time in years

$\quad \sf\dashrightarrow{1 \: days = \dfrac{1}{365}\: year}$

$\quad \sf\dashrightarrow{73 \: days = \dfrac{73}{365}\: year}$

$\quad \sf\dashrightarrow{73 \: days = \cancel\dfrac{73}{365}\: year}$

$\quad \sf\dashrightarrow{73 \: days = \dfrac{1}{5}\: year}$

$\quad \sf\dashrightarrow{73 \: days = \cancel\dfrac{1}{5}\: year}$

$\quad\bf\purple{\dashrightarrow{73 \: days = 0.2\: year}}$

$\begin{gathered}\end{gathered}$

$\bigstar{\underline{\underline{\frak{\blue{Calculating \: the \: Simple \: Interest \: :}}}}}$

$\quad{: \implies{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}$

• Substituting the values

$\quad{: \implies{\sf{S.I = \dfrac{10000 \times 0.2 \times 4}{100}}}}$

$\quad{: \implies{\sf{S.I = \dfrac{2000 \times 4}{100}}}}$

$\quad{: \implies{\sf{S.I = \dfrac{8000}{100}}}}$

$\quad{: \implies{\sf{S.I = \cancel\dfrac{8000}{100}}}}$

$\quad{\bf{\purple{: \implies{S.I = Rs.80}}}}$

$\quad\dag{\underline{\boxed{\sf{ \pink{Simple \: Interest = Rs.80}}}}}$

$\therefore{\underline{\underline{\sf{\red{The \: Simple \: Interest \: is \: Rs.80}}}}}$

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{Learn \: More ...}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{A ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{Amount = Principle + Interest}}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{ P=Amount - Interest }}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{ S.I = \dfrac{P \times R \times T}{100}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\blue{P = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}$