Question

The simple interest on some principal at sone rate for 3yrs is ₹525.At the same rate, the compound interest on ₹16000 for 2 yrs is ₹164.What is the principal?

Frnds plz ans fast with expalnation.....
plz its urgent

Answer 1

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Here is your answer in the attachment



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Answer 2

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Here is your answer
R = 3 years
SI = Rs 525
Let rate of interest= R and principal be x
Now
SI = PRT/100
$525 = \frac{x \times r \times 3}{100} \\ r = \frac{525 \times 100}{3x} \\ r = \frac{17500}{x} \%$
Hence For Compound Interest
T = 2 years
P = Rs 1600
CI = 164
R = 17500/x %
A = 1600 + 164 = Rs 1764
As we know the formula
A = P{1+R/100)^t
$1764 = 1600(1 + \frac{17500}{x \times 100} ) {}^{2} \\ \frac{1764}{1600} = (1 + \frac{175}{x} ) {}^{2} \\ \frac{441}{400} = (1 + \frac{175}{x} ) {}^{2} \\ ( \frac{21}{20} ) {}^{2} = (1 + \frac{175}{x} ) {}^{2} \\ on \: comparing \\ \frac{21}{20} = 1 + \frac{175}{x} \\ \frac{21}{20} - 1 = \frac{175}{x} \\ \frac{21 - 20}{20} = \frac{175}{x} \\ \frac{1}{20} = \frac{175}{x} \\ x = 175 \times 20 \\ x = 3500$
Therefore
Principal is Rs 3,500

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