Question

the simplified value of 1\√18is​

Answer 1

$\huge \frac{1}{ \sqrt{18} }$

$\huge \frac{1}{3 \sqrt{2} }$

$\huge \frac{ \sqrt{2} }{6 }$

Answer 2

${\huge{\tt{\red{Answer}}}}$

${\tt{ \frac{1}{ \sqrt{18} } }}$

Rationalize the denominator,

${\tt{ \frac{1 \times \sqrt{18} }{ \sqrt{18} \times \sqrt{18} } }}$

${\tt{ \frac{ \sqrt{18} }{18} }}$

${\tt{ \sqrt{18} = \sqrt{2 \times 3 \times 3} = 3 \sqrt{2} }}$

${\tt{ \frac{3 \sqrt{2} }{18} }}$

18 gets cancelled to 6 by 3. (3×6=18)

${\tt{ = \frac{ \sqrt{2} }{6} }}$