Question

The simultaneous equation 8x + 3y = 56 and 4x + 4y = 28 ​

Answer 1

Answer:

y=0,x=7

Step-by-step explanation:

8x+3y=56...(i)

4x+4y=28...(ii)

(i)-2(ii)

8x+3y=56

-8x-8y=-56

=-5y=0

=y=0

putting value of y in (ii)

4x+4*0=28

=4x=28

=x=28/4

=x=7

Answer 2

Step-by-step explanation:

Let,

=> 8x + 3y = 56 -----> (1)

=> 4x + 4y = 28 -----> (2)

We multiple equation (2) by (2)

=> 2.4x + 2.4y = 2.28

=> 8x + 8y = 56

Now,

Equation (1) - equation (2)

8x + 3y = 56

8x + 8y = 56

(-) (-) (-)

----------------------

0 -5y = 0

=> y = 0/5

=> y = 0

Substitute value of y in equation (2)

=> 4x + 4 × 0= 28

=> 4x + 0 = 28

=> x = 28/4

=> x = 7

Therefore, X = 0 and

Y = 7

Method used is Elimination method