Question

The size of isoelectronic species - $F^{-}$, Ne and $Na^{+}$ is affected by: (a) nuclear charge (Z) (b) valence principal quantum number (n) (c) electron–electron interaction in the outer orbitals (d) none of the factors because their size is the same

Answer 1

"Isoelectronic species are “different atoms” or “ions” with the “same number” of “electrons” but “different magnitudes” of “nuclear charges”.

The “size” of an “isoelectronic species increases” as the “nuclear charge (Z) decreases”.

For example, the “order” of the “increasing nuclear charge” of ${ F }^{ - }$, Ne and ${ Na }^{ + }$ is as follows.

${ F }^{ - }\quad <\quad Ne\quad <\quad N{ a }^{ + }$

Therefore, the order of the increasing size of${ F }^{ - }, Ne,$ and ${ Na }^{ + }$ is as follows.

$N{ a }^{ + }\quad <\quad Ne\quad <\quad { F }^{ - }$"

Answer 2

HEY MATE.......

THE ORDER IS

Na^+ < Ne < F^-