Question

The size of the interior angles of a triangle are in the ratio 3:4:5.Find the size of its largest number.

Answer 1

Answer:

5555555555555555555555555555555

Answer 2

Step-by-step explanation:

Correction :-

Find the size of the largest angle ?

Given :-

The size of the interior angles of a triangle are in the ratio 3:4:5.

To find :-

Find the size of its largest angle ?

Solution :-

Given that :-

The ratio of the interior angles of a triangle = 3:4:5

Let they be 3X° ,4X° and 5X°

We know that

Angle sum property

The sum of all the three interior angles of a triangle is 180°

=> 3X° + 4X° + 5X° = 180°

=> (3+4+5)X° = 180°

=> 12X° = 180°

=> X° = 180° /12

=> X° = 15°

So

If X° = 15° then

3X° = 3×15°= 45°

4X° = 4×15° = 60°

5X° = 5×15°=75°

So , The three interior angles of the given triaingle are 45° , 60° and 75°

The largest angle = 75°

Answer:-

The largest angle of the given triaingle = 75°

Check:-

The ratio = 45°:60°:75°

=> (3×15):(4×15):(5×15)

=> 3:4:5

And Their sum = 45°+60°+75°=180°

Verified the given relations in the given problem

Used formulae:-

Angle sum property:-

• The sum of all the three interior angles of a triangle is 180°