the size of the interior angles of a triangle are in the ratio 3:4:5 Find the size of its largest angle.(hint:the sum of the interior angles of a triangle is 180°)
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Answered by
4
Let the ratio be x.
So the required angles are 3x,4x and 5x.
a/q
3x+4x+5x=180
12x=180
x=15
Therefore size of largest angle=5x=5×15=75°
So the required angles are 3x,4x and 5x.
a/q
3x+4x+5x=180
12x=180
x=15
Therefore size of largest angle=5x=5×15=75°
Answered by
2
Ratio = 3 : 4 : 5
Define x:
Let x be the constant ratio
Ratio = 3x : 4x : 5x
Solve x:
The sum of angles in a triangle is 180º
3x + 4x + 5x = 180
12x = 180
x = 180 ÷ 12
x = 15º
Find the angles:
3x = 3(15) = 45º
4x = 4(15) = 60º
5x = 5(15) = 75º
Answer: The angles are 45º, 60º and 75º
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