Question

The size of the species V+2, V+3 and V+5 decreases as V+2 > V+3 > V+5 V+5 > V+3 > V+2 V+2 > V+5 > V+3 V+3 > V+2 > V+5

Answer 1

The size of the species V²⁺, V³⁺ and V⁵⁺ decreases as V²⁺ > V³⁺ > V⁵⁺.

- The atomic number of Vanadium (V) is 23.

- Initially, both the positive and negative charges are same.

- With the removal of electrons, the positive charge in the nucleus remians the same but the negative charge becomes less.

- Due to this, the effective nuclear charge becomes high and the size of the ion decreases with increasing charge.

- The ionic radii of the given species are:

V²⁺ = 93 pm

V³⁺ = 78 pm

V⁵⁺ = 68 pm

Answer 2

Answer:

e plus d equal c xd

Explanation:

E PLUS D EQUAL C XDDDDD E PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDDE PLUS D EQUAL C XDDDDD