the size z of a rhombus with diameter x and y is given by
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Answer:
z² = (x/2)² + (y/2)²
Step-by-step explanation:
Pythagoras theorem
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Answer:
in rhombus Let the point of intersection of the 2 diagonals be x
∴∠AOB=∠BOC=∠COD=∠DOA=90o ( Property of Rhombus)
In Triangle AOB,
∠AOB+∠OBA+∠BAO=180
90 + x + 40 = 180
x = 180 - 40- 90
x = 50
Similarly, We get y= 50.
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