Question

The slant height and base diameter of conical term aur 25 metre and 14m with respectively find the cost of whitewashing its curved surface area 210per hundred square

Answer 1

Answer

l = 25m

d = 14m

so,r = 14/2

r = 7m

CSA = πrl

= 22/7 x 7 x 25

= 550m^2

cost = 210/100^2

= 1m^2 = rs 2.1

= 2.1 x 550

= rs 1155

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Cost\:of\:white\:washing\:cone=1155\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given : }} \\ \tt: \implies Slant \: height = 25 \: m \\ \\ \tt: \implies Base \: diameter = 14 \: m \\ \\ \tt : \implies Cost \: of \: white \: washing = 210 \: rupees \: per \: 100 m^{2} \\ \\ \red{\underline \bold{To \: Find : }} \\ \tt: \implies Cost \: of \: white \: washing \: C.S.A = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt : \implies C.S.A\: of \: cone = \pi rl \\ \\ \tt : \implies C.S.A \: of \: cone = \frac{22}{7} \times 7 \times 25 \\ \\ \tt : \implies C.S.A\: of \: cone =22 \times 25 \\ \\ \green{\tt : \implies C.S.A\: of \: cone = 550 {m}^{2} } \\ \\ \bold{As \: according \: to \: question} \\ \tt: cost \: of \: white \: washing \: 100 {m}^{2} = 210 \\ \\ \tt: \implies Cost \: of \: white \: 1 \: {m}^{2} = \frac{210}{100} \\ \\ \tt: \implies Cost \: of \: white \: washing \: 550 {m}^{2} = \frac{210}{100} \times 550 \\ \\ \green{\tt: \implies Cost \: of \: white \: washing \: 550 {m}^{2} = 1155 \: rupees}$