Question

The slant height of a frustum of a cone is 4 m and the perimeter of circular ends are 18 m and 16 m. Find the cost of painting its curved surface area at 100 per sq. m.

Answer 1

Answer:

r1=18×7/2×22=63/22

r2=16×7/2×22=56/22

area of frustum =22/7(63/22+56/22)4

88/7(119/22)

68cm^2

cost=100×68=6800rs

Answer 2

Answer:

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