Question

The slant height of cone is 13cm and its height is 12cm find radius of cone base

Answer 1

Answer:

5

Step-by-step explanation:

(slant height)^2=(radius)^2+(height)^2

13^2=r^2 + 12^2

169=r^2 + 144

r^2=169-144

r^2=25

r=5

Answer 2

$Given:-$

• $Altitude \: \: of \: \: cone \: = \: 12 \: cm.$

• $slent \: \: height \: = \: 13 \: cm.$

$To \: \: Find:-$

• $Volume \: \: of \: \: cone$

$Solutions:-$

• $Using \: \: the \: \: Pythagoras \: \: theorem \: \: for \: \: find \: \: radius \: \: of \: \: cone.$

$⇢ l \: = \: \sqrt{{r}^{2} + {h}^{2}}$

$⇢ 13 \: = \: \sqrt{{r}^{2} + {12}^{2}}$

$⇢ 13 \: = \: \sqrt{{r}^{2} + {144}}$

$⇢ {13}^{2} \: = \: {r}^{2} + {144}$

$⇢ {169} - {144} \: = \: {r}^{2}$

$⇢ {25} = \: {r}^{2}$

$⇢ {r} = \: \sqrt{25}$

$⇢ {r} = \: {5}$

• $Volume \: \: of \: \: cone \: ⇢ \: \frac{1}{3} \: π{r}^{2}h$

$⇢ \: \frac{1}{3} \: × \: \frac{22}{7} \: × \: {5}{2} \: × \: {12}$

$⇢ \: \frac{22}{7} \: × \:{25} \: × \: {4}$

$⇢ \: {314.28} \: × \: {cm}^{3}$

$≫≫ hence, \: \: the \: \: volume \: \: of \: \: a \: \: right \: \: circular \: \: is \: 314.28 \: {cm}^{2}.$

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