The slope of the graph between log P and log V at constant temperature for a given mass of a gas is:- Kindly answer sir/mam. a) +1 b) -1 c) 1/T d) 1/n
Answers
Answered by
160
we know according to gases equation
PV=nRT
now take log both side
log(PV)=log (nRT)
logP +logV=log (nRT)
logP= (-1) logV +log (nRT)
question given temperature is constant and mass is also constant hence mole is constant , its mean nRT is constant .
so, log (nRT) is constant
now you see
logP=(-1) logV+log(nRT)
just like
y=mx+c
where y =logP
x=logV
c=log (nRT)
and m=-1
here m is slope of equation
so, slope =-1
PV=nRT
now take log both side
log(PV)=log (nRT)
logP +logV=log (nRT)
logP= (-1) logV +log (nRT)
question given temperature is constant and mass is also constant hence mole is constant , its mean nRT is constant .
so, log (nRT) is constant
now you see
logP=(-1) logV+log(nRT)
just like
y=mx+c
where y =logP
x=logV
c=log (nRT)
and m=-1
here m is slope of equation
so, slope =-1
abhi178:
please mark as brainliest
Answered by
68
P V = n R T
Mass is constant => n is constant. Given T is constant.
So P V = constant
Log P + Log V = constant
Log P = - Log V + constant
Slope of the straight line graph is -1.
Mass is constant => n is constant. Given T is constant.
So P V = constant
Log P + Log V = constant
Log P = - Log V + constant
Slope of the straight line graph is -1.
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