Question

the slope of the line is PQ is 2.where P (2,5) and Q(x, 3) then find the value of x? ​

Answer 1

Answer:-

Given:

P = ( 2 , 5)

Q = ( x , 3)

Slope of PQ = 2

We know that,

$slope \: of \: a \: line \: = \frac{ x_{2} - x_{1} }{y _{2} - y _{1} } \\ \\ 2 = \frac{x - 2}{3 - 5} \\ \\ 2 = \frac{x - 2}{ - 2} \\ \\ 2 (- 2) = x - 2 \\ \\ x - 2 = - 4 \\ \\ x = - 4 + 2 \\ \\ x = - 2$

Hence, the value of "x" is - 2.

Answer 2

Answer:

1 is the ans

Step-by-step explanation:

slope of line=(y2-y1)/(x2-x1)

here,

y2=3

y1=5

x2=x

x1=2

substituting values in abv eqn,

slope,m=(3-5)/(x-2)

        2=   -2/(x-2)            {given slope=2 in qs}

      solving we get,

x=1

hope it helps