Question

The slope of the line parallel to the line bx+ay+c=0 is​

Answer 1

Answer:

The given equation is ax+by+c=0

Therefore the slope of given equation is -a/b

since required line is perpendicular to given line,

the slope of required line is B/A

since the lines are passing through the the points (a,b)

by using slope point form,

(y-b) = (b/a)*(x-a)

a(y-b) = b(x-a)

ay-ab = bx-ab

ay = bx

Answer 2

Answer:

Required slope is (-b/a).

Step-by-step explanation:

Given line is $bx+ay+c=0$

The equation of a line in slope-intercept form is y = mx + b, where m is the slope of the line. To find the slope of a line parallel to the line bx+ay+c=0, we need to rearrange the equation into slope-intercept form.

$bx + ay + c = 0$

Subtracting bx and c from both sides:

$ay = -bx - c$

Dividing both sides by a:

$y = \frac{ - b}{a} x - \frac{c}{a}$

Therefore, the slope of the line bx + ay + c = 0 is -b/a. Any line parallel to this line will have the same slope, so the slope of the line parallel to bx + ay + c = 0 is also -b/a.

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