Question

The slope of the straight line 7x+14y+3=0 is

Answer 1

change the equation in y=mx+c form
7x+14y+3=0
14y=-7x-3
y=-1/2x-3/14
comparing the eq we get m=-1/2
so the slope is -1/2

Answer 2

Answer:

$Slope \: of \: given\\ \: straight\: line \:(m)=\frac{-1}{2}$

Step-by-step explanation:

$We\: know\:that \:,\\Slope\: of \: a \: straight\:line \:\\of \: the \: form \: ax+by+c=0 \: is \: \frac{-a}{b}$

\* Compare given straight line 7x+14y+3=0 with ax+by+c=0, we get

a=7, b = 14, c = 3

$Slope (m)\\ = \frac{-a}{b}\\=\frac{-7}{14}\\=\frac{-1}{2}$

Therefore,

$Slope \: of \: given\\ \: straight\: line \:(m)=\frac{-1}{2}$

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