Question

The smaller side of a rectangle is 6 cm less than that of its larger side .If its perimeter is

28 cm ,

a) What is the sum of the lengths of larger and smaller sides ?

b) What are the length of the sides ?​

Answer 1

let the larger side be x cm

smaller = x-6

perimeter = 2(l+b)

2( x+ x-6) =28

4x-12 = 28

x = 28+12/4=10

larger side = 10 cm

smaller = 10-6 = 4

a) sum of length = 4 + 10 cm = 14 cm

b) larger = 10 cm

smaller = 4 cm

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Answer 2

Given :

• The smaller side of a rectangle is 6 cm less than that of its larger side.
• Perimeter = 28 cm.

To Find :

• The sum of the lengths of larger and smaller sides?
• The length of the sides.

Solution :

According to the question :

Let, the larger side (L) of the rectangle be = (x)

then, the smaller side (B) will be = (x - 6)

༒ Using formula → P = 2(L + B)

⪼ 28 = 2(x + x - 6)

⪼ 28 = 2(2x - 6)

⪼ 28 = 4x - 12

⪼ 28 + 12 = 4x

⪼ 40/4 = x

⪼ x = 10

• Length of the larger side, L = x = 10
• Length of the smaller side, B = (x - 6) = 4

a) What is the sum of the lengths of larger and smaller sides ?

⪼ 10 + 4 = 14

b) What are the length of the sides ?

• 10 and 4