Math, asked by prealpha556, 1 year ago

The smallest 4digit number which is completely divisible by 47

Answers

Answered by Anonymous
0
ans.1034
solution.
first divide the smallest 4-digit number i.e. 1000 by 47
the remainder comes out to be 13
now subtract 13 from 1000. the answer will be 987.
this means latest 3 digital no. divisible by 47 is 987.
now add 47 to 987 to get the smallest 4digit no. divisible by 47. the answer will be 1034
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