Question

The smallest irrational number to be added to 3 + root 2 to get a rational
number is???

Answer 1

Step-by-step explanation:

The smallest irrational number is -

root2 since 3+ root2 +(-root2)

= 3+root2-root2

=3( a rational number).

Answer 2

Answer:

$-\sqrt{2}$ is a required  irrational number to be added to $3 + \sqrt{2}$ to get a rational number .

Step-by-step explanation:

Explanation:

Give , $3 + \sqrt{2}$

An irrational number is a actual variety that can not be expressed as a ratio of integers.

Any number  that may be written as a ratio of  integers is a rational number.

Step 1:

From the question we have $3 + \sqrt{2}$ ,in which $\sqrt{2}$ is a irrational number and 3 is a rational number.

Now , adding an irrational number  $-\sqrt{2}$  we get ,

$3 + \sqrt{2}$ + ($-\sqrt{2}$)

⇒3 .

Final answer :

Hence , $-\sqrt{2}$ is a irrational number to be added to $3 + \sqrt{2}$ to get a rational number .

#SPJ3